x^2+(3x-2)^2=116

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Solution for x^2+(3x-2)^2=116 equation: 



x^2+(3x-2)^2=116

We move all terms to the left:

x^2+(3x-2)^2-(116)=0

We move all terms containing x to the left, all other terms to the right

x^2+(3x-2)^2=116

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